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x-3y=13 and 5x+3y=2 using solving linear systems of elimination

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x-3y=13

5x+3y=2

asked Dec 7, 2013 in ALGEBRA 1 by skylar Apprentice

1 Answer

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Elimination method

Given equations are x-3y = 13 --------> (1)

5x+3y = 2 ---------> (2)

To eliminate the y value, add the equations (1)&(2).

x-3y = 13

5x+3y = 2

_________

6x = 15

Divide to each side by 6.

6x/6 =15/6

x = 5/2

Substitute the x value in (1).

5/2-3y = 13

-3y = 13-5/2

-3y = 21/2

Divide to each side by negitive 3.

-3y/-3 = 21/2*-3

y = -7/2

answered Dec 7, 2013 by william Mentor

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