3x+y=16 & 4x+2y=22 solve each system by substitution

Question

solve each system by substitution

3x + y = 16

4x + 2y = 22

Answer 1

Substitution method

Given first equation are 3x+y = 16

Subtract 3x from each side.

3x-3x+y = 16-3x

y = -3x+16 ---> (1)

Second equation 4x+2y = 22 ---> (2)

From (1) substitute the x value in (2).

4x+2(-3x+16) = 22

4x-6x+32 = 22

-2x+32 = 22

Subtract 32 from each side.

-2x = -10

Divide to each side by negitive 2.

⇒ x = 5

Substitute the x value in (1).

15+y = 16

Subtracct 15 from each side.

⇒ y = 1

Solution x = 5, y = 1.