Which two factors of x are roots of polynomial?

Question

3x^2 - 3x + 1.

Answer 1

3x^2-3x+1

Compare quadratic form is ax^2+bx+c.

a = 3, b = -3, c = 1

x = [-b±√(b^2-4ac)]/2a

x = [3±√(9-12)/6

x = [3±√-3]/6

x = [3±√3i]/6

x = (3+√3i)/6 and x = (3-√3i)/6

3x^2-3x+1 = [x-(3+√3i)/6][x-(3-√3i)/6]

Roots are x = (3+√3i)/6 and x = (3-√3i)/6.