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Find the roots of the polynomial equation x2 + 8x – 48 = 0

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I need HELP PLZZZ.

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roots-of-polynomials
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asked Feb 26, 2014 in ALGEBRA 1 by payton Apprentice

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1 Answer

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Given polynomial x^2+8x-48 = 0

x^2+12x-4x-48 = 0

x(x+12)-4(x+12) = 0

(x+12)(x-4) = 0

x+12 = 0

Subtract 12 from each side.

x+12-12 = 0-12

x = -12

and x-4 = 0

Add 4 to each side.

x-4+4 = 0+4

x = 4

Roots are -12,4.

answered Feb 26, 2014 by david Expert

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