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how to draw y^2=(x)/(1+x) graph

0 votes

i really have no idea how to do this

and roughly i know how the graph looks like but i don't know how to do the workings to draw it out

i appreciate your help very much

thank you.

asked Mar 4, 2014 in ALGEBRA 2 by payton Apprentice

2 Answers

0 votes
 
Best answer

The equation is y 2 = (x )/(1 + x ).

y = ± √[ (x )/(1 +x ) ].

Its, represents a rational function.

So, The rational function is y = ± √[ (x )/(1 + x ) ].

The graph of rational functions can be recognised by the fact two or more parts.

  • Find the vertical asympotote :

    Vertical asypototes are found  by equating the denominator is 0.

    ± √(1 + x ) = 0

1 + x = 0

x = - 1.

The vertical asymptote is x  = - 1.

  • Find the horizontal asympotote :

    To find horizontal asymptote,

    Degree of the numarator = 1 and the degree of denominator = 1.

    If the degree of the numerator is equals to the degree of the denominator

So, the line y = 1 is the horizontal asymptote.

  • Find the x - intercept :

Find the x - intercept by equationg the numarator is 0.

± √(x ) = 0

x = 0.

The x - intercept is zero.

  • Find the y - intercept :

To find y - intercept, substitute x = 0 in the rational function.

y = ± √[ (0)/(1 + 0) ].

y = 0.

The y - intercept is zero.

Now i will pick few more x - values, compute the corresponding y values and flat few more points.

x

y = ± √[ (x)/(1 + x) ]

(x, y )
- 5

y = ±√[ (- 5)/(1 + (- 5)) ] = ±√[ (- 5)/(- 4) ] = ±√(5/4)

(- 5, ±√(5/4))
- 4 y = ±√[ (- 4)/(1 + (- 4)) ] = ±√[ (- 4)/(- 3) ] = ±√(4/3) (- 4, ±√(4/3))
- 3 y = ±√[ (- 3)/(1 + (- 3)) ] = ±√[ (- 3)/(- 2) ] = ±√(3/2) (- 3, ±√(3/2))
- 2 y = ±√[ (- 2)/(1 + (- 2)) ] = ±√[ (- 2)/(- 1) ] = ±√2 (- 2, ±√2)
- 1 y = ±√[ (- 1)/(1 + (- 1)) ] = ±√[- 1/0] = ∞ not defined
0

y = ±√[ 0/(1 + 0) ] = 0

(0, 0)
1 y = ±√[ 1/(1 + 1) ] = ±√[1/2] (1, ±√[1/2])
2

y = ±√[ 2/(1 + 2) ] = ±√[2/3]

(2, ±√[2/3])
 

1) Draw the coordinate plane.

2) Next dash the horizontal and vertical asympototes

3) Plot the x intercept and coordinate pairs found in the table..

4) Connect the plotted points .

When you draw your graph, use smooth curves complete the graph.

answered Jun 12, 2014 by lilly Expert
selected Jun 13, 2014 by casacop
0 votes

Given expression is image.

Graph :

Graph of the expression image is

answered Mar 4, 2014 by dozey Mentor

The above graph does not represent a rational function.

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