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find the x-intercepts of the graph of f(x)= ln(x+1) - sin^2 x

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find the x-intercepts of the graph of f(x)= ln(x+1) - sin^2 x.
asked Mar 11, 2014 in GEOMETRY by harvy0496 Apprentice

1 Answer

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The x-intercepts are where f = 0.

The equation ln(x+1) - (sin(x))² cannot be solved analytically for x.

You might happen to notice that it has a solution at x = 0.

x-intercepts can be obtained when y=0.

From a graph of f(x) you can tell there are two other solutions when f(x) ie., y=0.

They are one near x = 1 and one near x = 1.7 (more precise values are 0.9643632012096066 and 1.683885012285295, according to WolframAlpha)

Therefoe the x-intercepts are 0.9643632012096066 and 1.683885012285295.

answered May 19, 2014 by joly Scholar

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