Welcome :: Homework Help and Answers :: Mathskey.com
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,459 questions

17,854 answers

1,446 comments

811,646 users

f(x)=-2(x-1)^2+5

0 votes
Graphing a Quadratic Function in Standard Form.

 

asked Feb 27, 2014 in GEOMETRY by dkinz Apprentice

2 Answers

0 votes

f(x) = -2(x-1)^2+5

y = -2(x^2+1-2x)+5

y = -2x^2-2+4x+5

y = -2x^2+4x+3

Now it is in standard form of parabola y = ax^2+bx+c

Graph

 

answered Feb 27, 2014 by david Expert
0 votes

The function is f(x) = y = - 2(x - 1)2 + 5.

Rewrite the function as f(x) = y = - 2x2 + 4x + 3.

The standard form of quadratic function is f(x) = ax2 + bx + c.

Step 1 :

Find the axis of symmetry :

Formula for the equation of the axis of symmetry:  x = - b/2a.

Substitute the values of b = 4 and a = - 2 in the formula, x = - b/2a.

x = - 4/2(- 2)

x = - 4/- 4 = 1.

The equation for the axis of symmetry is x = 1.

Step 2 :

Find the vertex :

To find the vertex, use the value of equation for the axis of symmetry as the  x - coordinate of the vertex.

To find the y - coordinate, substitute the value of x = 1 in the original function, y = - 2x2 + 4x + 3.

y = - 2(1)2 + 4(1) + 3

y = - 2 + 4 + 3 = 7 - 2

y = 5.

The vertex is (1, 5).

Determine whether the function has maximum or minimum value :

The value of a = - 2 < 0 (negative), so the graph of function opens downward and has a maximum value.

The maximum value (y - coordinate of the vertex) is 5.

Step 3 :

Find the y -  intercept :

To find the y - intercept, Substitute the value x = 0 in the original function, f(x) = y = - 2x2 + 4x + 3.

y = - 2(0)2 + 4(0) + 3

y = 3.

The y - intercept is 3.

Step 4 :

  • Lets find the another point.Choose an x - value of - 1 and substitute.The new point is at (- 1, - 3).
  • The point paired with it on other side of the axis of symmetry is (3, - 3) and has the same y - value.
  • Since, The axis of symmetry devides the parabola into two equal parts.So, if there is a point (- 1, - 3) on one side, there is a corresponding point on other side that is the same distance from the axis of symmetry and has the same y - value.
  • The distance between the points (-1, - 3) and (1, -3) = 2 = The distance between (1, - 3) and the point paired with it on other side of the axis of symmetry and has the same y - value.
  • The distance between (1, - 3) and the point paired with it on other side of the axis of symmetry. = 1 + 2 = 3.
  • Therefore, The point paired with it on other side of the axis of symmetry is (3, - 3).
  • The y - intercept is (0, 3), so the point paired with it on other side of the axis of symmetry is (1, 3) and has the same y - value.
  • Therefore, The point paired with it on other side of the axis of symmetry is (2, 3).
  • Connect these points and create a smooth curve.

Graph :

The graph of function f(x)=x^2+6x-6

answered Jun 3, 2014 by lilly Expert
edited Jun 3, 2014 by lilly

Related questions

asked Jul 5, 2016 in PRECALCULUS by anonymous
...