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what are the roots for the quadratic equation 3x^2+6x-24=0.

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Please help, i need help fast!!!! thanks so muchhhh!!!!!

asked Feb 17, 2014 in ALGEBRA 2 by linda Scholar

1 Answer

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Given equation 3x^2+6x-24 = 0

Compare it to quadratic form ax^2+bx+c = 0

a = 3, b = 6, c = -24

Roots are x = [-b±√(b^2-4ac)]/2a

x = [-6±√(36+288)]/6

x = [-6±√324]/6

x = [-6±18]/6

x = [-6+18]/6 and x = [-6-18]/6

x = 12/6 and x = -24/6

x = 2 and x = -4

Roots of 3x^2+6x-24 = 0 are 2,-4.

answered Feb 17, 2014 by ashokavf Scholar

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