please solve the quadratic equation and show your work x^2-2x-13=0

Question

please solve the quadratic equation suing the indian method and show your work x^2-2x-13=0.

Answer 1

Given equation x^2-2x-13 = 0

Compare it to quadratic form ax^2+bx+c = 0.

a = 1, b = -2, c = -13.

x = [-b±√(b^2-4ac]/2a

x = [2±√(4+52)]/2

x = [2±√56]/2

x = [2±7.48]/2

x = 9.48/2 and x = -5.48/2

Solution x = 4.74 and x = -2.74.

 

Answer 2

The steps are

(a) Move the constant term to the right side of the equation.

(b) Multiply each term in the equation by four times the coefficient of the x2 term.

(c) Square the coefficient of the original x term and add it to both sides of the equation.

(d) Take the square root of both sides.

(e) Set the left side of the equation equal to the positive square root of the number on the right side and solve for x.

(f) Set the left side of the equation equal to the negative square root of the number on the right side of the equation and solve for x.

contd..

Step (e): Set the left side of the equation to the positive square root of the number on the right side and solve for x

you get:

x = (√(56)+2)/2

x = (-√(56)+2)/2

source: http://openstudy.com/updates/4f5eba4de4b0602be4393554