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x^2+7x=-2x^2+6

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put the problem in the form of ax^2+bx+c=0.
asked Mar 11, 2014 in ALGEBRA 2 by chrisgirl Apprentice

1 Answer

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 The equation is x ^2 + 7x  = - 2 x ^2 + 6.

The equation convert to the form of ax ^2 + bx + c = 0.

x ^2 + 7x  = - 2 x ^2 + 6.

Subtract 2 x ^2 from each side.

3 x ^2 + 7x  = 6.

Subtract 6 from each side.

3 x ^2 + 7x - 6 = 0.

The quadratic form : 3 x ^2 + 7x - 6 = 0.

answered Mar 22, 2014 by friend Mentor
edited Mar 22, 2014 by friend

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