Question

2x^2 + 3x - 10 using quadratic formula.

Answer 1

Given equation 2x^2+3x-10

Compare it to quadratic form ax^2+bx+c = 0

a = 2, b = 3, c = -10

Roots are x = [-b±√(b^2-4ac)]/2a

x = [-3±√(9+80)]/4

x = [-3±√89]/4

x = [-3±9.43]/4

x = [-3+9.43]/4 and x = [-3-9.43]/4

x = 6.43/4 and x = -12.43/4

Solution x = 1.6075 and x = 3.1075.