graph the points using these two linear equations 3x+y=10 and 2x-y=5

Question

Solving 4 ways of linear equations

Answer 1

Given  equations are 3x+y = 10 and 2x-y = 5

Now find coordinate points of each equation.

x is half coordinate point and y is half coordinate point.

First linear equation is 3x+y = 10

Subtract 3x from each side.

3x-3x+y = 10-3x

y = -3x+10

For x = 0 ⇒y  = 10

For x = 1 ⇒y = 7

for x = 2 ⇒y = 4

If  x = 0,1,2 respectively,then the set of coordinate pair is 10,7,4.

We can able to write the points are (0,10),(1,7),(2,4)

And now second linear eqution is 2x-y = 5

Subtract 2x from each side.

2x-2x-y = 5-2x

-y = 5-2x

Multiple to each side negitive one.

y = -5+2x

y = 2x-5

similarly if x = 0,1,2 respectively, then the set of coordinate pair is -5,-3,-1.

we can able to write the points are (0,-5),(1,-3),(2,-1)

Graph of above linear equations.

Draw a coordinate plane.

recognise the points.

Observe the two equations are intersecting when x = 3,y = 1

From the graph solution is x = 3, y = 1

Check

substitute x,y in first equation.

3*3+1 = 10

10 = 10