Question

Find the intercepts of (x^2)(y) - x^2 + 4y = 0.

Answer 1

The equation is x ^2(y) - x ^2 + 4y = 0.

To find x - intercept substitute y = 0 in given equation.

x ^2(0) - x ^2 + 4(0) = 0

0 - x ^2 + 0 = 0

- x ^2 = 0

x ^2 = 0 ⇒ x = 0.

To find y  - intercept substitute x = 0 in given equation.

0^2(y) - 0^2 + 4y = 0

0 - 0 + 4y = 0

4y = 0 ⇒ y = 0.

Therefore, x and y intercepts of the given equation are 0, 0.