what is the perimeter of a field with a length of 6 meters and an area of 85 square meters?

Question

The field consists of a rectangle of length L, and width W, and a semicircle that is symmetrical about the central horizontal axis of the rectangle.

Answer 1

Field length(L ) = 6m

Field width = W m

Area of rectangular field (A ) = L * W

A = 85 squre meters

85 = 6 * W

W  = 85/6

W  = 14.16m

Perimater of rectangular feild (P ) = 2(L +W )

P  = 2(6+14.16)

P  = 40.32

Perimeter of field = 40.32 meters.