What is the center of the circle with coordinates (-3,3) and (6,-2)

Answer 1

Let us assume that, the two points (- 3, 3) and (6, - 2) are the endpoints of the diameter of a circle.

Let the points are (x₁, y₁) = (- 3, 3) and (x₂, y₂) = (6, - 2).

The center of the circle is the midpoint of the line segment (- 3, 3) and (6, - 2).

Mid point = [ (x₁ + x₂)/2, (y₁ + y₂)/2 ]

               = [ (- 3 + 6)/2, (3 - 2)/2 ]

               = [ 3/2, 1/2 ].

So,the midpoint is the center of circle is (3/2, 1/2).

Answer 2

Let us assume that, the two points (- 3, 3) and (6, - 2) are the endpoints of the diameter of a circle.

Let the points are (x₁, y₁) = (- 3, 3) and (x₂, y₂) = (6, - 2).

The center of the circle is the midpoint of the line segment (- 3, 3) and (6, - 2).

Mid point = [ (x₁ + x₂)/2, (y₁ + y₂)/2 ]

               = [ (- 3 + 6)/2, (3 - 2)/2 ]

               = [ 3/2, 1/2 ].

So,the midpoint is the center of circle is (3/2, 1/2).