Divide using long division?

Question

27x^4+9x^3+6x^2/3x^2+2
State the quotient and remainder

Answer 1

The expression

Divide the first term of the dividend by the first term of the divisor 27x⁴/3x² = 9x².

So,the first term of the quotient is 9x².Multiply (3x² + 2) by 9x² and subtract.

Divide the first term of the last row by first term of the divisor 9x³/3x² = 3x.

So,the second term of the quotient is 3x. Multiply (3x² + 2) by 3x and subtract.

Divide the first term of the last row by first term of the divisor  (- 12x²)/3x² = - 4.

So,the third term of the quotient is (- 4). Multiply (3x² + 2) by (- 4) and subtract.

Quotient is 9x² + 3x - 4 and remainder is - 6x + 8.