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How do I solve for x:

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x^4-1/x^3=0
asked Aug 26, 2013 in ALGEBRA 1 by andrew Scholar

1 Answer

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Given that x^4 - 1/x^3 = 0

x^4 = 1/x^3

(x^4)(x^3) = 1

(x^(4+3)) = 1               (from formula a^m . a^n = a^m+n)

(x^7) = 1

Take seventh root on both sides

(x^7)^1/7 = (1)^1/7

x = 1

verification -

x^4 - 1/x^3 = 0

(1)^4 - 1/(1)^3 = 0

1 - 1 = 0

L.H.S = R.H.S

 

answered Aug 27, 2013 by jouis Apprentice

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