Perimeter of a triangle with the coordinates of (-2,9) and (7,-3) and (-2,-3)

Question

i need help please

Answer 1

Let A(-2,9) , B(7,-3), C(-2,-3)

Assume ABC is triangle.

Find the sides of triangle.

Find the distance between the coordinates.

AB = √[(7+2)^2+(-3-9)^2]

=√(81+144) = 15

BC =√[(-2-7)^2+(-3+3)^2]

= √(81+0) = 9

CA = √[(-2+2)^2+(9+3)^2]

= √(0+144)

= 12

Perimeter of triangle = AB+BC+CA = 15+9+12

= 36