what is the perimeter of the triangle with vertices (-1,6) (7,0) and (0,-1)

Question

college algebra do not understand it

Answer 1

Let the triangle vertices  A(-1,6) B(7,0)C(0,-1)

Assume ABC is a triangle.

Now find the lengths of triangle.

AB = √[(7+1)^2+(0-6)^2]

= √(64+36)

= 10

BC = √[(0-7)^2+(-1-0)^2]

= √(49+1)

= √50

CA = √[(-1-0)^2+(6+1)^2]

= √(1+49)

= √50

Perimeter = AB+BC+CA

= 10+√50+√50

= 10+2√50