Find the vertices and foci for each X^2/1+y^2/4=1

Question

i really need helpwith this

Answer 1

x^2/1+y^2/4 = 1

(x-0)^2/1^2+(y-0)^2/2^2 = 1

If the large denominator is under the y term,then the ellipse is vertical.

Sandard equation x^2/b^2+y^2/a^2 = 1, a > b

h = 0,k = 0,a = 2,b = 1

vertices are (h,k+a)(h,k-a)

(0,0+2)(0,0-2)

vertices are(0,2)(0,-2)

c = √(a^2-b^2)

c = √(4-1)

c = √3

Foci(0,√3)(0,-√3)