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(3x^7-9)(x^8-9) foil method

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i need to use the foil system.
asked Mar 11, 2014 in ALGEBRA 2 by johnkelly Apprentice

1 Answer

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Foil method :

(a+b)(c+d) = \underbrace{ac}_\mathrm{first} + \underbrace{ad}_\mathrm{outside} + \underbrace{bc}_\mathrm{inside} + \underbrace{bd}_\mathrm{last}

The polynomial is (3x ^7 - 9)(x ^8 - 9)

= (3x ^7)(x ^8) + (3x ^7)(- 9) + (- 9)(x ^8) + (- 9)(- 9)

= 3x ^15 - 27x ^7 - 9x ^8 + 81.

Therefore, (3x ^7 - 9)(x ^8 - 9) = 3x ^15 - 27x ^7 - 9x ^8 + 81.

answered Mar 28, 2014 by lilly Expert

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