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(3√5-2√2)(4√5+2√2)

four radicals.

asked Mar 11, 2014 in ALGEBRA 1 by johnkelly Apprentice
reshown Mar 12, 2014 by goushi

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1 Answer

( 3 √5 - 2 √2 ) ( 4 √5 + 2√2)

= ( 3 √5 ) ( 4 √5 ) + ( 3 √5 ) (2 √2 ) - ( 2 √2 )( 4 √5 ) - ( 2√2) ( 2√2).

= 12 (√5 )² + 6 ( √5 * √2 ) - 8 ( √2 * √5 ) - 4 ( √2 ) ²

= 12 ( 5 ) + 6 ( √10 ) - 8 √10 - 4 ( 2 )

= 60 - 2√10 - 8

= 52 - 2√10

= 2 ( 26 - √10 ).

Therefore ( 3 √5 - 2 √2 ) ( 4 √5 + 2√2) = 2 ( 26 - √10 ).

answered Apr 2, 2014 by friend Mentor

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