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Solve for A

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R1= the sqaure root of A/π -R2^2
asked Nov 6, 2014 in ALGEBRA 2 by doan12345 Pupil

1 Answer

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R1 = sqaure root of (A/π -R2^2)

Take square each side

r1^2 = A/π -R2^2

Add R2^2 to each side

R1^2 + R2^2 = A/π

Multiply each side by π

π(R1^2 + R2^2 ) = A

answered Nov 6, 2014 by anonymous

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