What's the centre of circles

1 Answer

Passes through the fixed points are (a, 0) and (-a, 0)

Mid point of center of circle is [(a-a)/2, (0+0)/2] = [0, 0]

The radius is distance between the two numbers.

So, r = √[(a-(-a))²+ (0-0)²]

r = √[2a]² = 2a

Cartesian coordinates

In an x–y Cartesian coordinate system, e circle with Centre coordinates (a, b) and radius r is the set of all points (x, y) such that (x - a)² + (y - b)² = r²

point (0, 0) and radius r = 2a.

So, (x - 0)² + (y - 0)² = (2a)²

x² + y² = 4a².

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What's the centre of circles

which always passes through the fixed points (a,0) and (-a,0) ?

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1 Answer

Cartesian coordinates

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