State the equation of this circle:

Question

Centre (-1, -1) through the point (4,0)?

Answer 1

The standard form of circle equation (x - h)² + (y - k)² = r²

Where (h, k) center and r is radius of circle.

Substitute for(x, y) = (4, 0) and (h ,k ) = (- 1, - 1) in standard form.

[4 - ( - 1)]² + [0 - (- 1)]² = r²

( 4 + 1)² + (0 + 1)² = r²

25 + 1 = r²

r² = 26

Substitute r² = 26 and (h ,k ) = (- 1, - 1) in standard form.

[x - (- 1)]² + [y - (- 1)]² = 26

Required equation (x + 1)² + (y + 1)² = 26.