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Simplify 2cos^2x - sinx

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into terms of sinx?

asked Jun 17, 2014 in TRIGONOMETRY by anonymous

1 Answer

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The expression is 2cos2x - sinx

=2 (1- sin2x) - sin               [Using pythagorean identity: cos2x = 1-sin2x]

= 2 - 2sin2x - sinx                  

answered Jun 17, 2014 by joly Scholar
edited Jul 31, 2014 by bradely

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