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1+secx/tanx+sinx

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Solve this problem using trig identities.

1+secx/tanx+sinx

trigonometric-identities

asked Nov 30, 2013 in TRIGONOMETRY by mathgirl Apprentice

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1 Answer

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Recall the trigonometric identities

secx = 1/cosx, tanx = sinx/cosx , cscx = 1/sinx

1+secx/tanx+sinx

= (1+1/cosx)/(sinx/cosx)+sinx

= ((cosx+1)/cosx)/((sinx+sinxcosx)/cosx)

= (cosx+1)/sinx(1+cosx)

= 1/sinx

= cscx

answered Nov 30, 2013 by william Mentor

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