Verify the proof: (secx+tanx)/(cscx+1)=tanx.

Question

thank you

Answer 1

Left hand side identity

= (Secx+Tanx)/(Cscx+1)

= [1/Cosx+Sinx/Cosx]/[1/Sinx+1}

= [1+Sinx/Cosx]/[1+Sinx/Sinx]

= Sinx/Cosx

= Tanx

= Right hand side identity.