Welcome :: Homework Help and Answers :: Mathskey.com

Q&A
Unanswered
Categories
Users
Ask a Question

Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

Q&A Categories
BASIC MATH (93)
PRE-ALGEBRA (441)
ALGEBRA 1 (2,220)
GEOMETRY (864)
ALGEBRA 2 (2,751)
TRIGONOMETRY (1,187)
PRECALCULUS (1,903)
CALCULUS (2,802)
STATISTICS (129)
PHYSICS (659)
CHEMISTRY (137)
MECHANICAL ENGINEERING (64)
ELECTRICAL ENGINEERING (207)
Winplot Tutorials (2)

Most popular tags

solving-equations system-of-equations functions math slope-intercept-form physics homework-help trigonometric-identities integration limits substitution-method calculus

13,459 questions

17,854 answers

1,446 comments

811,146 users

find derivative if y=(secx+tanx)(secx-tanx)

0 votes

trigonometric-identities

asked Dec 8, 2016 in CALCULUS by anonymous

Share this question

Google+ Facebook Twitter LinkedIn Reddit

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 votes

The equation is

Sum or difference property:

Apply sum or difference property of the equation.

Trigonometric identity:

Differentiate on each side with respect to .

The derivative of is

answered Dec 8, 2016 by Anney Mentor

Please log in or register to add a comment.

Related questions

Find tanx+secx

asked Sep 20, 2018 in TRIGONOMETRY by anonymous

trigonometric-identities
trignometric-ratios

prove that (secx+tanx)(1-sinx/cosx)=1

asked Aug 27, 2014 in PRECALCULUS by anonymous

trigonometric-identities
precalc
trig

[cosx(tanx-secx)]/(1-cscx)=sinx Verify identity

asked Mar 1, 2014 in TRIGONOMETRY by johnkelly Apprentice

trigonometric-identities
solving-trigonometric-equations

secx+tanx=cosx

asked Mar 1, 2014 in TRIGONOMETRY by payton Apprentice

trigonometric-identities
solving-trigonometric-equations

How do I cerify the identity tanx sinx + cosx = secx

asked Feb 18, 2014 in TRIGONOMETRY by payton Apprentice

trigonometric-identities

Verify the proof: (secx+tanx)/(cscx+1)=tanx.

asked Feb 12, 2014 in TRIGONOMETRY by mathgirl Apprentice

trigonometric-identities

cosx + sinx + tanx = secx verify this

asked Nov 30, 2013 in TRIGONOMETRY by homeworkhelp Mentor

trigonometric-identities

1+secx/tanx+sinx

asked Nov 30, 2013 in TRIGONOMETRY by mathgirl Apprentice

trigonometric-identities

Verify the identity. cosx+sinx tanx=secx

asked Nov 20, 2013 in TRIGONOMETRY by abstain12 Apprentice

trigonometric-identities

For what values of x does f(x)=(secx)/(1+tanx) have a horizontal tangent?

asked Aug 12, 2014 in CALCULUS by anonymous

equation-of-a-tangent-line
calculus

Simplify the expression secx/sinx - sinx/cosx

asked Mar 1, 2014 in TRIGONOMETRY by mathgirl Apprentice

trigonometric-identities
solving-trigonometric-equations

(cosx)/(1-sinx)=2(secx)

asked Mar 1, 2014 in TRIGONOMETRY by rockstar Apprentice

trigonometric-identities
solving-trigonometric-equations

Prove sinx/cscx + cosx/secx = 1

asked Feb 24, 2014 in TRIGONOMETRY by linda Scholar

trigonometric-identities
solving-trigonometric-equations

Prove ((cscx-cotx)(cscx+cotx))/secx=cosx

asked Feb 24, 2014 in TRIGONOMETRY by dkinz Apprentice

trigonometric-identities
solving-trigonometric-equations

cosx(secx-cosx)=sin^2x

asked Nov 30, 2013 in TRIGONOMETRY by payton Apprentice

trigonometric-identities

varify the identity: csc^2(X) - (CosX)(SecX) = Cot^2(X)

asked Nov 20, 2013 in TRIGONOMETRY by mathgirl Apprentice

trigonometric-identities

tanx + cotx = 2 csc 2x

asked Feb 21, 2014 in TRIGONOMETRY by dkinz Apprentice

trigonometric-identities
solving-trigonometric-equations

(TanX-1)(CosX-1)=0

asked Feb 18, 2014 in TRIGONOMETRY by skylar Apprentice

trigonometric-identities

1 / tanx (1 + cos2x) = csc2x

asked Nov 30, 2013 in TRIGONOMETRY by johnkelly Apprentice

trigonometric-identities

Verify the identity: (sinx + tanx + tan^3x)/tanx = cosx + sec^2x

asked Nov 20, 2013 in TRIGONOMETRY by homeworkhelp Mentor

trigonometric-identities

Copyright © 2024 MATHSKEY. All Rights Reserved. Sitemap|Terms Of Use|Disclaimer|Contact Us|FAQ

...