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Is f(x) = 1/(x^2-5x)

0 votes

odd or even?

odd-even
functions

asked Jul 11, 2014 in ALGEBRA 2 by anonymous

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1 Answer

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Let f (x) be the real value function.

Remember that :

Even : f (- x) = f (x).
Odd : f (- x) = - f (x).

The function f (x) = 1/(x² - 5x).

f (- x) = 1/[(- x)² - 5(- x)] = 1/(x² + 5x).

So, the function neither odd nor even.

answered Jul 11, 2014 by lilly Expert

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