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geometric sequence

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Find an equation for the nth term of a geometric sequence where the second and fifth terms are -21 and 567, respectively.
asked Aug 4, 2014 in CALCULUS by Tdog79 Pupil

1 Answer

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nth term in geometric sequence is arn-1

a = first term, r = common ratio.

In the sequence 2nd term is -21 and 5th term is 567

2nd term is ar2-1 = -21

ar = -21 ---> (1)

And 5th term is ar5-1 = 567

ar4 = 567

(ar)r3 = 567

From (1) substitute the value of ar.

-21r3 = 567

r= 567/-21

r= -27

r3   = (-3)3

r = -3

Substitute the value of r in equation (1).

-3a = -21

a = 7

First term is 7.

nth term is 7(-3)n-1.

answered Aug 4, 2014 by david Expert

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