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Identify the 12th term of a geometric sequence

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where a1 = 8 and a6 = -8,192.

geometric-series

asked Jul 22, 2013 in ALGEBRA 1 by harvy0496 Apprentice

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1 Answer

0 votes

Given that a1 = 8 and a6 = -8,192

a1 = a = 8 =>1

r = -4

Asked to find a12

a12 = 8(-4194304)

a12 = -33554432

Therefore the value of a12 is -33554432

answered Jul 26, 2013 by jouis Apprentice

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