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limit

+1 vote

Use graphs and tables to find the limit and identify any vertical asymptotes of the function. 

limit of 1 divided by the quantity x minus 10 as x approaches 10 from the left

asked Aug 4, 2014 in CALCULUS by Tdog79 Pupil

1 Answer

+1 vote

The function is f(x) = 1/(x - 10).

The table lists the value of f(x) for several x-values approaches 10 from the left.

x

f(x) = 1/(x-10)

[x, f(x)]

9.5

f(x) = 1/(9.5 - 10) = 1/(-0.5) = - 2

(9.5, -2)

9.9

f(x) = 1/(9.9 - 10) = 1/(-0.1) = - 10

(9.9, - 10)

9.99

f(x) = 1/(9.99 - 10) = 1/(-0.01) = - 100

(9.99, -100)

9.999

f(x) = 1/(9.999 - 10) = 1/(-0.001) = - 1000

(9.999, -1000)

9.9999

f(x) = 1/(9.9999 - 10) = 1/(-0.0001) = - 10000

(9.9999, -10000)

9.99999

f(x) = 1/(9.99999 - 10) = 1/(-0.00001) = - 100000

(9.99999, -100000)

10 f(x) = 1/(10 - 10) = - 1/0 = - ∞ (10, -∞)

 

The function f(x) = 1/(x-10) graph is

 

Observe the graph and table,

when x approaches 10 from the left, (x - 10) is a small negative number. Thus, the quotient 1/(x-10) is a large negative number and f(x) approaches negative infinity from left side of x = 10. So, we can conclude that x = 10 is a vertical asymptote of the graph of f(x) and

image

 

answered Aug 4, 2014 by casacop Expert

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