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How to solve linear equation?

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Solve linear equation by substitution method.
3x-y=2
5x-2y=6

asked Mar 1, 2013 in ALGEBRA 1 by johnkelly Apprentice
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2 Answers

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3x-y=2 -----------> y = 3x - 2
substitute y = 3x - 2 in 5x-2y=6
5x - 2(3x-2)=6
5x - 6x + 4 = 6
-x + 4 = 6
x=-2
substitute x=-2 in y = 3x - 2
y=3*-2 - 2
y = -6 - 2 = -8
(x, y) = (-2, -8)

answered Mar 1, 2013 by casacop Expert
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substitute y = 3x - 2 in 5x-2y=6
5x - 2(3x-2)=6
5x - 6x + 4 = 6
-x + 4 = 6
x=-2
substitute x=-2 in y = 3x - 2
y=3*-2 - 2
y = -6 - 2 = -8
(x, y) = (-2, -8)

solution is (-2,-8).

answered Mar 5, 2013 by Naren Answers Apprentice

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