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Differentiate with respect to X 6x^2-5x^2+1/3x^2

+1 vote

derivatives

asked Mar 1, 2013 in PRECALCULUS by Afeez Novice
recategorized Mar 1, 2013 by steve

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1 Answer

+1 vote

= d/dx(6x^2-5x^2+1/3x^2)

= d/dx(x^2+1/3x^2)

= d/dx( (1+1/3)x^2)

= 4/3 d/dx(x^2)

= 4/3 * 2x

= 8/3 x

answered Mar 1, 2013 by steve Scholar

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