I'm a little confused on this problem ...

Question

Put the equation in the form of ax^2 + bx + c = 0

 

7-3x^2 = (x+2)^2 - 6

7- 3x ^2  = x^2 +8x  + 4 - 6

7 - 4x^2 + 8x  -2

9 - 4x^2 + 8x

-4x^2 + 8x - 9

.....................

Answer 1

Apply the formula

Bring all terms to left side of equal sign.

Multiply each side by negative one.

Now it is in the form of .

a  = 4, b  = 4, c  = - 9.