sketch graph Q3

Question

1. Sketch the graph xy=-10 1.1. Is the graph of xy=-10 discontinuous? 2. Skecth the graph of (x^2/16) + (y^2/9) =1 2.1. Is the above graph in 2 asymmetric about the x-axis or not? 3. Sketch and clearly indicate the area bounded by the graph of y=3x^2 - 12, the x-axis ; x=0 and x=2. Also, indicate the representative to be used to calculate the area shown. 3.1. Calculate using integration, the magintude of the area indicated in Q3.

Answer 1

(1).

The function is xy = - 10 and its grsph is

Comments

(1.2).

From the graph, the function is continuous at every real number in the domain of the function.

The function is nonremovable discontinuity at x = 0.

In other words, there is no way to define f(0) so as to make the function continues at x = 0.

Answer 2

(2).

The equation is .

Write equation in standard form .

Vertices: (a, 0) = (4, 0) and (-4, 0) = (-6, 0)

Co-vertices: (0, b) = (0, 3) and (0, -b) = (0, -3).

Major axis = 2a = 2(4) = 8

Minor axis = 2b = 2(3) = 6

Graph:

(2.1).

Vertices are symmetrical about y-axis and co-vertices are symmetrical about x-axis.

Yes, the graph is symmetrical about x-axis.

Answer 3

(3).

The equation is y = 3x^2-12 and its graph is

(3.1).

.