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sketch graph Q3

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1. Sketch the graph xy=-10 1.1. Is the graph of xy=-10 discontinuous? 2. Skecth the graph of (x^2/16) + (y^2/9) =1 2.1. Is the above graph in 2 asymmetric about the x-axis or not? 3. Sketch and clearly indicate the area bounded by the graph of y=3x^2 - 12, the x-axis ; x=0 and x=2. Also, indicate the representative to be used to calculate the area shown. 3.1. Calculate using integration, the magintude of the area indicated in Q3.
asked Oct 15, 2014 in ALGEBRA 2 by anonymous

3 Answers

0 votes

(1).

The function is xy = - 10 and its grsph is

answered Oct 15, 2014 by casacop Expert

(1.2).

From the graph, the function is continuous at every real number in the domain of the function.

The function is nonremovable discontinuity at x = 0.

In other words, there is no way to define f(0) so as to make the function continues at x = 0.

0 votes

(2).

The equation is image.

Write equation in standard form image.

image

Vertices: (a, 0) = (4, 0) and (-4, 0) = (-6, 0)

Co-vertices: (0, b) = (0, 3) and (0, -b) = (0, -3).

Major axis = 2a = 2(4) = 8

Minor axis = 2b = 2(3) = 6

Graph:

(2.1).

Vertices are symmetrical about y-axis and co-vertices are symmetrical about x-axis.

Yes, the graph is symmetrical about x-axis.

answered Oct 16, 2014 by casacop Expert
0 votes

(3).

The equation is y = 3x^2-12 and its graph is

(3.1).

image.

answered Oct 16, 2014 by casacop Expert

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