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Solve this problem

0 votes

a-b^-2 / b-a^2

-simply
complex
fraction

asked Oct 18, 2014 in ALGEBRA 2 by doan12345 Pupil

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1 Answer

+1 vote

The expression is (a - b^-2)/(b - a²).

Rewrite b^-2 as 1/b².

= [a - (1/b²)] / (b - a²)

= [(ab² - 1)/b²] / (b - a²)

= (ab² - 1) / b²(b - a²)

= (ab² - 1) / (b³ - b²a²).

answered Oct 18, 2014 by casacop Expert

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