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Given the function

0 votes

g(x)=3+2x^2 g^-1(a)? 

asked Oct 21, 2014 in ALGEBRA 2 by anonymous

1 Answer

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The function g(x) = 3 + 2x2

Change g(x) to y.

y = 3 + 2x2

Interchange x and y.

x = 3 + 2y2

Solve for y.

x - 3 = 2y2

y2 = (x - 3)/2

Apply square root on each side.

y = ± √[(x - 3)/2]

Change y to g-1 (x).

g-1 (x) = ± √[(x - 3)/2]

g-1 (a) = ± √[(a - 3)/2].

answered Oct 21, 2014 by david Expert

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