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let P(x,y) be a point on the graph of y=4x. Express the distance d from P to the point (-1,0) as a function of x

options 


a) d=√17xˆ2 +2x+1 .


b) d=√17xˆ2 +1 


c) d=√17xˆ2 +4x+1 


d) d=√17xˆ2 +8x+1 


e) d=√17xˆ2 -8x+1 


f) d=√17xˆ2 -2x+1

asked Oct 21, 2014 in CALCULUS by anonymous

1 Answer

0 votes

The points are P(x, y) and (-1, 0).

Substitute (x1, y1) = (x, y) and (x2, y2) = (-1, 0) in the distance fromula: d = √[(x2 - x1)2 + (y2 - y1)2].

d = √[(-1 - x)2 + (0 - y)2]

d = √[1 + 2x + x2 + y2]

The point P(x, y) lie on the line y = 4x.

d = √[1 + 2x + x2 + (4x)2]

d = √(1 + 2x + 17x2)

d = √(17x2 + 2x + 1).

The option a is correct.

answered Oct 21, 2014 by casacop Expert

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