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Suppose (x^2)/64 + (y^2)/64 = 1 and y( 3 ) = 7.41620.

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Find y'( 3 ) by implicit differentiation.?

implicit-differntiation

asked Oct 25, 2014 in ALGEBRA 1 by anonymous

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1 Answer

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The Equation is .

Re-write the equation

x² + y² = 64.

Apply differentiation on each side.

Therefore .

Given that y(3) = 7.41620 which means that at x =3, y = 7.14620

Then substitute x = 3 and y = 7.41620

Therefore y'(3) = -0.4198.

answered Oct 25, 2014 by dozey Mentor

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