how do i find the X intercept of

Question

y=2(x+2)^2-1

Answer 1

The equation is y = 2(x+2)² - 1.

To find x-intercept substitute y = 0 in the original equation_.

2(x+2)² - 1 = 0

2(x+2)² = 1

(x+2)² = 1/2

x+2 = ± √(1/2)

x = - 2 ± √(1/2)

The x-intercepts are x = - 2 + √(1/2) and x = - 2 - √(1/2).