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f(t)=6.91e^.011t find f(0), f'(0), f(8), and f'(8)? 

asked Nov 6, 2014 in CALCULUS by anonymous

1 Answer

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The exponential function f(t) = 6.91e0.011t

f(0) = 6.91e0.011(0)

= 6.91e0

= 6.91(1)

f(0) = 6.91

 

f(8) = 6.91e0.011(8)

= 6.91e0.088

= 6.91(1.0919)

f(8) = 7.545

 

f(t) = 6.91e0.011t

f'(t) = 6.91e0.011t(0.011)

f'(t) = 0.07601 e0.011t

 

f'(0) = 0.07601 e0.011(0)

f'(0) = 0.07601 e0

f'(0) = 0.07601

 

f'(8) = 0.07601 e0.011(8)

= 0.07601 e0.088

= 0.07601(1.0919)

f'(8) = 0.08299.

answered Nov 6, 2014 by david Expert

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