A spaceship lifts off vertically from the moon,

Question

 where the free-fall acceleration is 1.6 m/s2. If the spaceship has an upward acceleration...? 

 

A spaceship lifts off vertically from the moon, where the free-fall acceleration is 1.6 m/s2. If the spaceship has an upward acceleration of 2.3 m/s2 as it lifts off, what is the force of the spaceship on an astronaut who weighs 765 N on Earth?

 

Answer 1

The weight of astronaut on earth is 765 N .

Gravitational constant on earth g = 9.8 .

So the mass of the astronaut is 765 / 9.8 = 78.06 kgs .

The free-fall acceleration on the moon is (g_moon) 1.6 m/s² .

The upward acceleration of spaceship is (a)2.3 m/s² .

The force of the spaceship on an astronaut is F = m( a+g_moon )

F = 78.06( 2.3 +1.6 )

F = 78.06( 3.9 )

F = 304.4 N

So the force of the spaceship on an astronaut is 304.4 N .