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I'm having a bit of trouble with displacement and velocity.

0 votes

 

1. How would i hive the displacement of this graph?

2. What is the velocity of the robot as it goes from gate 3 to gate 4?

3. What is the average speed of the robot over the entire experiment?

asked Nov 9, 2014 in PHYSICS by hana_24 Novice

3 Answers

0 votes

(1)

The displacement is the change in an object's position.

Displacement is the difference between an object's initial position and its final position.

Displacement has a magnitude and direction and is therefore a vector.

The final position of the robot is  2 m .

The initial position of the robot is 0 m .                    [since it starts from rest ]


Displacement D = final position - initial position 

                      D = 2 m - 0 m

                     D = 2 m 

So the displacement of the robot is 2 m .

answered Nov 10, 2014 by yamin_math Mentor
edited Nov 10, 2014 by bradely
0 votes

(2)

Velocity is the rate of change of the position of an object .

Change in its position from gate 3  to gate 4 is 0.8 m - 0.6 m = 0.2 m .

The duration of time to cross gate 3  to gate is 1.2 sec - 1.05 sec = 0.15 sec .

So the velocity of robot as it goes from gate 3 to gate 4 is 0.2 m / 0.15 s

                                                                                           = 20 m / 15 s 

                                                                                           = 1.334 m/s .

The velocity of robot as it goes from gate 3 to gate 4 is  1.334 m/s .

answered Nov 10, 2014 by yamin_math Mentor
0 votes

(3)

The average speed is can evaluated using the below mentioned formula  .

Average speed = total distance traveled / time interval .

Total distance travelled is = d1 + d2 + d3 + d4 + d5 + d6 + d7 + d8 + d9 + d10    [since the experiment was done with 10 instantaneous values ] 

                                        = 0.2 +0.2 +0.3 +0.1 +0.2 +0.2 +0.2 +0.2 +0.2 +0.2

                                        = 2 m 

Total distance travelled is 2 m .

Total time is = t1 + t2 +t3 +t4 +t5 +t6 +t7 +t8 +t9 +t10

                   = 0.6 + 0.3 +0.15 + 0.15 +0.15 +0.1 +0.25 +0.4 +0.6 +0.4

                   = 3 sec 

Duration of time = 3 sec .

So average speed = 2 / 3 

                                  = 0.667 m/s 

The average speed of the robot over the entire experiment is 0.667 m/s .

answered Nov 10, 2014 by yamin_math Mentor

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