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helppp please!4

0 votes
function y=x^2 - 4x - 5, determine the following characteristic gor this function.

- number of x intercepts

-number of y intercepts

- number of turing point

- range and domain

- End behavior
asked Nov 12, 2014 in CALCULUS by anonymous

5 Answers

0 votes

(1)

y = x² - 4x - 5 .

To determine the number of x-intercepts of the graph of a quadratic function, substitute 0 for y  .
0 = x² - 4x - 5
 x² - 4x - 5 = 0
 x² - 5x + x - 5 = 0
x(x-5) +1(x-5) = 0
(x-5)(x+1) = 0
x-5 = 0 and x+1 = 0
x = 5 and x = -1
So the function has two x-intercepts .
answered Nov 12, 2014 by yamin_math Mentor
0 votes

(2)

y = x² - 4x - 5 .

To determine the number of y-intercepts of the graph of a quadratic function, substitute 0 for x  .
y = 0² - 4(0) - 5 
y = 0 - 0 -5
y =-5
So the function has one y-intercepts .
answered Nov 12, 2014 by yamin_math Mentor
0 votes

 

(3)

The function is y = x² - 4x - 5 .

Turning points are nothing but the local minimum / maximum .

To find the local minimum / maximum , equate the first derivative to zero .

y' = 2x - 4

 2x - 4 = 0

2x = 4

x = 4/2

x = 2

So the function has one turning point at x = 2 .

 

answered Nov 12, 2014 by yamin_math Mentor
0 votes

 

(4)

The function is y = x² - 4x - 5 .

We first put the equation in to the form for a translated parabola y = (h )^2 + .

Rewrite the function 

y = x² - 4x - 5

y = x² - 4x + 4 - 4 - 5

y = x² - 4x + 4 - 9

y = (x-2)² - 9

The above function represents a parabola vertex form  y = (h )^2 + .

  = 1 , h  = 2 and k  = -9 .

a  is positive number the parabola opens up and has minimum value.

When the parabola opens up it has a minimum point which is the vertex of parabola ( 2, -9)

We know that domain of the function is all possible x  values and range is all posible y  values.

 parabola domain x  =  all real numbers.

In the minimum point y  = -9  so the graph of parabola cannot be lower than -9.

Thus the range of function y  ≥ -9.

Domain of function is all real numbers.

Range of the function is  {|y  ≥ -9}.

 

answered Nov 12, 2014 by yamin_math Mentor
0 votes

(5)

The function is y = x² - 4x - 5 .

The end behavior of a polynomial function is the behavior of the graph of f(x) as approaches positive infinity or negative infinity.

The degree and the leading coefficient of a polynomial function determine the end behavior of the graph.

The given function has the even degree and leading coefficient is positive .

 So, the end behavior is: image 

answered Nov 12, 2014 by yamin_math Mentor

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