Welcome :: Homework Help and Answers :: Mathskey.com
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,459 questions

17,854 answers

1,446 comments

805,810 users

Helppp!10

0 votes
Determine the degree,the leading coefficient,and the constant term for each polynomial function.

a) f(x) = 5x^2 + 2x - 7

b) f(x) = -3x + 11

c) f(x) = 3/4 x^2 - 6x^2 + 8x + 2
asked Nov 12, 2014 in CALCULUS by anonymous

3 Answers

0 votes
 
Best answer

a)

Given function f(x) = 5x² + 2x - 7

degree :

The degree of a polynomial is the highest degree of its terms when the polynomial is expressed in its canonical form consisting of a linear combination of monomials.

leading coeficient :

The coefficient of the term with the highest degree (greatest power of x) is called the leading coeficient and cannot equal 0.

constant term :

The term for which degree is zero.

The degree = 2

The leading coefficient = 5

The constant term = -7

answered Nov 12, 2014 by Shalom Scholar
0 votes

b)

Given function f(x) = - 3x + 11

f(x) = - 3x¹ + 11

The degree = 1

The leading coefficient = - 3

The constant term = 11

answered Nov 12, 2014 by Shalom Scholar
0 votes

c)

Given function f(x) = 3/4 x² - 6x² + 8x + 2

f(x) = (3/4 - 6)x² + 8x + 2

f(x) = (-21/4)x² + 8x + 2

The degree = 2

The leading coefficient = (-21/4)

The constant term = 2

answered Nov 12, 2014 by Shalom Scholar

Related questions

asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 13, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
...