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Help with a parametrics question!?

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The chord of contact of two tangents drawn from an external point P to the parabola x^2=8y has equation x + 2y - 3 = 0. Find the coordinates of P. 
 
 
 
asked Nov 12, 2014 in PRECALCULUS by anonymous

1 Answer

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The parabola is  image and the  chord of contact is x + 2 y - 3 = 0.

From the equation of chord of contact, image  ....................( 1 )

Rewriting the equation x + 2y - 3 = 0 that is 2y +x -3 =0

image     ..................( 2 )

Comparing equations (1) and (2),

image  and  image

The equation of parabola in parametric form is  image.

image

 image

       = image

So the value of  a = 2 .

The point of intersection of tangents is  ( a(p+q),apq ).

a ( p + q ) = 2( -1)  = - 2  and image.

So, the  coordinates of P are ( -2 , -3/2 ).

answered Nov 12, 2014 by saurav Pupil

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