physics question help please!!?

Question

A uniform electric field exists between two oppositely charged parallel plates connected to a 13.0V battery. The plates are separated by 7.00x10^-4 m.

 

a) Determine the magnitude of the electric field between the plates

b) If a charge of -4.29x10^-6 C moves from one plate to another, calculate the change in electric potential energy of the charge.

 

Answer 1

a)

Find the magnitude of the electric field between the plates by using the relation:

E = V/d

   = (13) / (7.00x10^-4 )

   = 1.857x10^4  Volts/m

Answer 2

b)

Find the change in potential energy of the charge.by using the formula:

PE = qEd

   = (4.29x10^-6 )(1.857x10^4) (7.00x10^-4)

    = 55.77 x 10^-6 J