physics question help please

Question

A 5.9 cm tall object is placed 39 cm in front of a convex mirror with a radius of curvature of

58 cm.

a) What is the image distance?

b) What is the size of image produced?

c) State whether the image is: real or virtual, erect or inverted, and larger or smaller than the

object.

Answer 1

a)

Object height h_object = 5.9 cm

Object distance d_object = 39 cm

Image distance d_image = ?

Radius of curvature C = 58 cm

Focal length f= C/2 = 58/2 = 29 cm

Formula for convex mirror is

Solution : Image distance is 113.1 cm.

Answer 2

b)

The negative values for image height indicate that the image is an inverted image.

Solution : Image size (height) is 17.11 cm.

Answer 3

c)

Properties of Convex mirror image are

a) Virtual

b) Upright and Erect

c) Smaller in size

d) Image located behind (Opposite side of object) the convex mirror and located between Mirror and Focal point.

Solution : The image is virtual , erect and smaller than the object.